This question was previously asked in

SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )

Option 2 : 14 / 45

Cell

339239

10 Questions
10 Marks
7 Mins

**Given**

The probability of getting plumbing contract = P(A) = 2/3

Probability of getting not electric contract P(B̅) = 5/9

Probability of getting atleast one contract P(A U B) = 4/5

**Calculation**

The probability of not getting electric contract = 1 - P(B̅)

⇒ = 1- 5/9 = 4/9

Probability of getting both the contracts P(A ∩ B) = P(A) + P(B) - P(A U B)

⇒ P(A ∩ B) = 2/3 + 4/9 - 4/5

⇒ (90 + 60 - 108)/135

**∴ The probability that he will get both the contracts P(A ∩ B) is 14/45**